NTA CSIR UGC NET December Online Form 2025

• Short Description :

National Testing Agency (NTA) – National Testing Agency (NTA) has released the notification for CSIR UGC NET December 2025. Online applications will be accepted from 25 September 2025 to 24 October 2025, with the correction window open from 27–29 October 2025. The examination is scheduled on 18 December 2025, and the admit card will be released before the exam. This test covers Chemical Science, Life Science, Mathematical Science, Physical Science, and Earth Sciences. Candidates with a Master’s degree (55% for General, 50% for reserved categories) are eligible. Apply online through csirnet.nta.nic.in.

NTA CSIR UGC NET December 2025
NTA CSIR NET Limited Application Form 2025
Important Dates Application Fees
  • Online Apply Start: 25 September 2025
  • Apply Last Date: 24 October 2025
  • Last Date For Fees: 25 October 2025
  • Correction Date: 27-29 October 2025
  • Admit Card Date: Notified Soon
  • Exam Date: 18 December 2025
  • Result Date: Undeclared
  • General / EWS: ₹1150/-
  • OBC-NCL Candidates: ₹600/-
  • SC / ST / PwD: ₹325/-
  • Payment Method: Online (Debit card / Credit Card), Net banking, UPI
Age Limit (As on 01.08.2025) Total Posts
  • JRFMaximum 30 Years as on 01 December 2025
  • Lecture/NET: No age limit
  • Use Age Calculate Tool Click Here

  • NA
Vacancy Detail – Total Posts (NA)
Exam Name Subjects Offered Eligibility
NTA CSIR NET Exam – December 2025
  • Chemical Science
  • Earth, Atmospheric, Ocean & Planetary Science
  • Life Science
  • Mathematical Science
  • Physical Science
  • Master’s degree with at least 55% marks (50% for OBC-NCL/SC/ST/PwD).
  • Final year students or those awaiting results may also apply (Master’s must be completed within 2 years for JRF/PhD or within 1 year for PhD only).
  • 4-year Bachelor’s degree holders with 75% marks (5% relaxation for reserved categories) can apply for JRF + PhD, but not for Assistant Professor.
  • For complete details, refer to the official notification.
How To Apply For The NTA CSIR NET Limited Application 2025
  • Apply only through official website or the direct link provided in the “Important Links” section.
  • Read the official notification carefully before applying.
  • Prepare required documents, photo, and signature in the correct format.
  • Review your application form before final submission.
  • Use the “Apply Online” link given below in the Important Links section.
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Important Links
Online Apply Click Here
Download Notification Click Here
Telegram Channel Telegram
Whatsapp Channel Click Here
Official Website Click Here

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FAQs – NTA CSIR UGC NET December 2025
Q1. When does the application process for CSIR NET December 2025 start?
Ans. The online application process starts on 25 September 2025.
Q2. What is the last date to apply for CSIR NET December 2025?
Ans. The last date to apply online is 24 October 2025.
Q3. When is the last date for fee payment?
Ans. The last date for fee payment is 25 October 2025.
Q4. What are the correction dates for CSIR NET December 2025?
Ans. The correction window will be open from 27 to 29 October 2025.
Q5. When will the CSIR NET December 2025 exam be held?
Ans. The exam will be conducted on 18 December 2025.
Q6. What is the application fee for CSIR NET December 2025?
Ans.
• General / EWS: ₹1150/-
• OBC-NCL: ₹600/-
• SC / ST / PwD: ₹325/-
Q7. What is the age limit for CSIR NET December 2025?
Ans.
• JRF: Maximum 30 years as on 01 December 2025
• Lectureship/NET: No age limit
Q8. What are the subjects offered in CSIR NET December 2025?
Ans. Chemical Science, Life Science, Mathematical Science, Physical Science, and Earth, Atmospheric, Ocean & Planetary Science.
Q9. What is the eligibility for CSIR NET December 2025?
Ans. Master’s degree with minimum 55% marks (50% for reserved categories). Final year students may also apply. 4-year Bachelor’s degree holders with 75% marks are eligible for JRF + PhD.
Q10. What is the official website to apply for CSIR NET December 2025?
Ans. Candidates can apply through the official website csirnet.nta.nic.in.